Pick what you want, print the page. The answer key comes with it, on its own sheet, and it tells you the mistake behind every wrong choice — not just which letter is right.
This exact URL always produces this exact sheet — bookmark it and the answer key will still match next term. Print with your browser; the controls and the site navigation are left off the page.
1.How many different four-letter arrangements can be made from the letters of the word MATH, using each letter once?[4]
A4
B12
C16
D24
E256
2.In how many ways can 7 be written as the sum of two different whole numbers bigger than zero? Swapping the order does not make a new way.[4]
A3
B4
C6
D7
E12
3.In a class of 30 students, 18 play football and 15 play chess. Exactly 7 students do both. How many students play neither?[4]
A4
B26
C3
D11
E7
4.How many two-digit numbers have digits that add up to 8?[5]
A4
B7
C8
D9
E16
5.On a 4 by 4 board, how many aligned squares of any size are there, counting 1 by 1, 2 by 2, 3 by 3 and 4 by 4?[5]
A16
B20
C26
D30
E36
6.Five beads of five different colours are threaded on a circular bracelet. Two bracelets count as the same if one can be turned or flipped into the other. How many different bracelets are there?[5]
A12
B20
C24
D60
E120
7.How many three-digit whole numbers contain at least one digit 7?[5]
A243
B252
C271
D280
E648
8.How many squares of any size can be found on a 3 by 3 board?[5]
A9
B10
C12
D13
E14
9.What is the smallest number n such that ANY collection of n whole numbers must contain two of them whose difference is divisible by 7?[5]
A8
B7
C14
D15
E4
10.How many diagonals does a convex polygon with 12 sides have? A diagonal joins two vertices that are not already joined by a side.[5]
A54
B66
C108
D120
E42
Kangaroo Atlas · https://kangaroo-atlas.vercel.app · seed 3 · CC BY-NC-SA 4.0 · Independent project, not affiliated with Math Kangaroo in USA, NFP.
Answer key — Math Kangaroo practice
Each wrong choice carries the thinking that produces it. When a student picks C, this is what they were doing.
1.D — 24KA-0073Arrangements of a few objects
AI counted the letters rather than their arrangements.
BI multiplied 4 by 3 and stopped, forgetting the last two positions.
CI used 4 choices for every position, as if letters could repeat.
EI used 4 choices in each of four positions, which allows every letter to repeat.
2.A — 3KA-0076Casework
BI included 0 and 7 as a pair, even though both numbers have to be bigger than zero.
CI counted both orders of each pair, even though swapping does not make a new way.
DI counted every starting number from 1 to 7 without checking which pairs repeat.
EI counted both orders and also allowed pairs of equal numbers.
3.A — 4KA-0154Inclusion–exclusion with two sets
BI found how many students play at least one of the two and answered with that instead.
CI added 18 and 15 to get 33, subtracted the 30 in the class, and used the 3 left over.
DI removed the 7 from both groups and subtracted 11 and 8 from 30, taking the overlap away twice.
EI answered with the number who play both, which is what the question gave me rather than what it asked for.
4.C — 8KA-0012Casework
AI counted each pair of digits once instead of counting both orders, such as 17 and 71.
BI listed the pairs starting from 1 and 7 and forgot the number 80, where the second digit is zero.
DI included 08 as a two-digit number, but a two-digit number cannot start with zero.
EI counted both orders of every pair and then counted the pairs that reverse to themselves twice as well.
5.D — 30KA-0047Counting by position (sliding window)
AI counted only the sixteen smallest squares and stopped there.
BI counted the small squares and the single big one, and forgot every size in between.
CI counted the 2 by 2 squares as four rather than nine, splitting the board into blocks.
EI used 4 by 4 positions for every size instead of shrinking the range as the square grows.
6.A — 12KA-0071Overcount, then correct
BI divided the 120 arrangements by 6 rather than by the 10 movements that leave a bracelet looking the same.
CI allowed for turning the bracelet but forgot it can also be flipped over.
DI halved the 120 for flipping but forgot that turning also gives the same bracelet.
EI counted every arrangement in a line, as if the bracelet had a fixed first bead.
7.B — 252KA-0075Complementary counting
AI counted the numbers made entirely of digits other than 7 in every position, including a leading zero.
CI counted the numbers with a 7 in each position separately and forgot that some were counted twice.
DI added three lots of 90 and one extra hundred, double counting the 700s.
EI counted the numbers with no 7 at all and gave that instead of subtracting it.
8.E — 14KA-0133Counting shapes hidden inside a figure
AI counted the nine small squares and stopped, missing every larger one.
BI counted the small squares and the whole board, forgetting the middle size entirely.
CI found the 2 by 2 squares by splitting the board into blocks, getting two instead of four.
DI slid the 2 by 2 square across and down but missed one of its four positions.
9.A — 8KA-0175The pigeonhole principle
BI used the number of possible remainders without adding one for the pair that must collide.
CI doubled 7, thinking I needed two full sets of remainders.
DI doubled 7 and added one, applying the pigeonhole idea to the wrong number of boxes.
EI guessed from small cases without identifying what the boxes actually are.
10.A — 54KA-0177Overcount, then correct
BI counted every line joining two vertices and forgot to remove the 12 sides.
CI counted each diagonal from both of its endpoints and forgot to halve.
DI used 12 x 10 without halving, double counting every diagonal.
EI subtracted 24 rather than 12, removing each side twice.