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1.On the number line shown, the marks are equally spaced. What number does the arrow point to?[3]
Text description of the figure
A number line with equally spaced tick marks. The leftmost tick is labelled 0 and the rightmost is labelled 60, with five unlabelled ticks evenly spaced between them. An arrow points to the fourth tick from the left.
A4
B24
C30
D40
E50
2.Today is Tuesday. What day of the week will it be in 100 days?[3]
AMonday
BTuesday
CWednesday
DThursday
EFriday
3.A jacket costs 80 euros. Its price is reduced by 25%. What is the new price?[3]
A20
B40
C45
D55
E60
4.One bus leaves every 12 minutes and another every 18 minutes. They leave together at 9:00. When do they next leave together?[3]
A9:06
B9:30
C9:36
D9:54
E12:36
5.In the number 4073, what is the value of the digit 7?[3]
A3
B7
C70
D700
E4000
6.What is 1 + 2 + 3 + ... + 20?[3]
A190
B200
C210
D220
E420
7.Three quarters of a class of 28 travelled by bus. How many did not travel by bus?[3]
A4
B7
C12
D21
E24
8.Which of these fractions lies between one third and one half?[3]
A1/5
B1/4
C2/5
D3/5
E2/3
9.What is the remainder when 2 to the power 50 is divided by 7?[3]
A1
B2
C4
D6
E0
10.What is the remainder when 7 to the power 100 is divided by 5?[3]
A1
B2
C3
D4
E0
11.The four-digit number 27_4 is divisible by 3. Which digit could go in the gap?[4]
A1
B2
C3
D4
E6
12.Red and blue counters are in the ratio 3 to 5. There are 40 counters altogether. How many are red?[4]
A5
B8
C13
D15
E24
13.The mean of five numbers is 12. One of the numbers is removed and the mean of the remaining four is 11. What number was removed?[4]
A1
B11
C12
D16
E23
14.What is the remainder when 2 to the power 30 is divided by 7?[4]
A1
B2
C4
D5
E6
15.The two digits of a number are swapped and the number gets bigger by 36. Which of these could be the number?[4]
A13
B15
C24
D41
E62
16.What is 2 + 4 + 6 + ... + 100?[4]
A1275
B2450
C2500
D2550
E5100
17.24 pencils and 36 erasers are shared into identical gift bags, using every item. What is the largest number of bags possible?[4]
A4
B6
C12
D18
E72
18.What is the units digit of 3 multiplied by itself 100 times, that is 3 to the power 100?[4]
A1
B3
C7
D9
Eit cannot be found without a calculator
19.A and B are different digits. The two-digit number AB added to the two-digit number BA gives 132. What is A + B?[5]
A3
B6
C11
D12
E13
20.How many two-digit numbers have both of their digits odd?[5]
A10
B20
C25
D45
E50
Kangaroo Atlas · https://kangaroo-atlas.vercel.app · seed 1 · CC BY-NC-SA 4.0 · Independent project, not affiliated with Math Kangaroo in USA, NFP.
Answer key — Math Kangaroo practice
Each wrong choice carries the thinking that produces it. When a student picks C, this is what they were doing.
1.C — 30KA-0006Number lines and betweenness
AI counted the tick marks and gave the position number instead of reading the value on the scale.
BI worked out that each gap is worth 10 but then counted only as far as the tick before the arrow.
DI counted the tick marks rather than the gaps between them, so every gap came out one step too small.
EI counted the gaps from the right-hand end instead of from zero.
2.D — ThursdayKA-0021Remainders and modular cycles
AI found the remainder 2 but counted the two days starting from today rather than starting from tomorrow.
BI divided 100 by 7 and used the quotient of 14, treating the leftover days as if there were none.
CI remembered there was a remainder but used a remainder of 1 instead of working it out.
EI counted 100 divided by 7 as 14 remainder 3 instead of remainder 2.
3.E — 60KA-0026Percentages and simple discounts
AI worked out the size of the discount and gave that as the new price instead of subtracting it.
BI treated a quarter off as half off and took the price down to 40.
CI applied the 25% reduction twice, taking 80 down to 60 and then 60 down to 45.
DI subtracted 25 euros rather than 25 percent, treating the percentage as an amount of money.
4.C — 9:36KA-0041Factors, multiples, LCM and GCD by listing
AI found the greatest common divisor of 12 and 18 instead of the least common multiple.
BI added the two intervals together rather than looking for a time that is a multiple of both.
DI found a common multiple but not the least one, landing on a later coincidence.
EI multiplied the two intervals together instead of finding their least common multiple.
5.C — 70KA-0055Place value and digit positions
AI gave the last digit of the number instead of looking at the 7 at all.
BI gave the digit itself rather than what it is worth in the position it sits in.
DI counted the positions from the left, so I read the 7 as being in the hundreds place.
EI gave the value of the largest digit instead of the value of the 7.
6.C — 210KA-0057Clever regrouping (pair to round numbers)
AI paired the numbers from the outside in but left the 20 out of every pair, so I added only up to 19.
BI estimated the total as a round number instead of working it out.
DI used eleven pairs of 20 instead of ten pairs of 21.
EI multiplied 20 by 21 and forgot that pairing counts every number twice.
7.B — 7KA-0064Fractions of a quantity
AI divided 28 by 7 instead of taking a quarter of it.
CI found three quarters of 16 by mistake, mixing up the class size.
DI found how many did travel by bus and gave that instead of how many did not.
EI subtracted the 4 quarters as if they were 4 students.
8.C — 2/5KA-0141Number lines and betweenness
AI compared the bottom numbers and assumed a bigger denominator means a bigger fraction.
BI saw that 4 lies between 3 and 2 and assumed one quarter therefore lies between the two fractions.
DI checked that it is bigger than one third but never checked it against one half.
EI compared the top numbers only and ignored what the bottoms do to the size.
9.C — 4KA-0161Remainders and modular cycles
AI assumed the cycle ends on 1 at every exponent that is a multiple of 2.
BI used a remainder of 1 rather than 2 when dividing 50 by 3.
DI doubled my way to 2 cubed = 8 and used 8 minus 2.
EI assumed a large power of 2 must eventually be divisible by 7.
10.A — 1KA-0169Remainders and modular cycles
BI reduced 7 to 2 correctly but then used a remainder of 1 when dividing 100 by 4.
CI read the cycle backwards and landed on the entry before the right one.
DI used 100 divided by 4 giving 25 and read off the 25th entry as if the cycle had length 25.
EI assumed a power that large must be divisible by 5.